Close menu
Close menu

Tunnistaudu

Kirjaudu

Etkö ole vielä jäsen?

Liity jäseneksi

Formelblad

Download PDF document »

Number Rules

$a\cdot0=0$a·0=0 $1\cdot a=a$1·a=a

 

Expand Rules

$-\left(a\pm b\right)=-a\mp b$(a±b)=ab $a\left(b+c\right)=ab+ac$a(b+c)=ab+ac
$a\left(b+c\right)\left(d+e\right)=abd+abe+acd+ace$a(b+c)(d+e)=abd+abe+acd+ace $\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$(a+b)(c+d)=ac+ad+bc+bd
$-\left(-a\right)=a$(a)=a $$

 

Fractions Rules

$\frac{0}{a}=0\:,\:a\ne0$0a =0 , a0 $\frac{a}{1}=a$a1 =a
$\frac{a}{a}=1$aa =1 $\left(\frac{a}{b}\right)^{-1}=\frac{1}{\frac{a}{b}}=\frac{b}{a}$(ab )1=1ab  =ba 
$\left(\frac{a}{b}\right)^{-c}=\left(\left(\frac{a}{b}\right)^{-1}\right)^c=\left(\frac{b}{a}\right)^c$(ab )c=((ab )1)c=(ba )c $a^{-1}=\frac{1}{a}$a1=1a 
$a^{-b}=\frac{1}{a^b}$ab=1ab  $\frac{-a}{-b}=\frac{a}{b}$ab =ab 
$\frac{-a}{b}=-\frac{a}{b}$ab =ab  $\frac{a}{-b}=-\frac{a}{b}$ab =ab 
$\frac{a}{\frac{b}{c}}=\frac{a\cdot c}{b}$abc  =a·cb  $\frac{\frac{b}{c}}{a}=\frac{b}{c\cdot a}$bc a =bc·a 
$\frac{1}{\frac{b}{c}}=\frac{c}{b}$1bc  =cb  $$

 

Absolute Rules

$\left|-a\right|=a$|a|=a $\left|a\right|=a\:,\:a\ge0$|a|=a , a0
$\left|-a\right|=\left|a\right|$|a|=|a| $\left|ax\right|=a\left|x\right|\:,\:a\ge0$|ax|=a|x| , a0

 

Exponent Rules

$1^a=1$1a=1 $a^1=a$a1=a
$a^0=1\:,\:a\ne0$a0=1 , a0 $0^a=0\:,\:a\ne0$0a=0 , a0
$\left(ab\right)^n=a^nb^n$(ab)n=anbn $\frac{a^m}{a^n}=a^{m-n}\:,\:m>n$aman =amn , m>n
$\frac{a^m}{a^n}=\frac{1}{a^{n-m}}\:,\:n>m$aman =1anm  , n>m $a^{b+c}=a^ba^c$ab+c=abac
$\left(a^b\right)^c=a^{b\cdot c}$(ab)c=ab·c $a^{bx}=\left(a^b\right)^x$abx=(ab)x
$\left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}$(ab )c=acbc  $a^{\frac{m}{n}}=\left(\sqrt[n]{a}\right)^m$amn =(na)m
$a^c\cdot b^c=\left(a\cdot b\right)^c$ac·bc=(a·b)c $\sqrt[n]{a\cdot b}=\sqrt[n]{a}\sqrt[n]{b}$na·b=nanb

 

Factor Rules

$x^2-y^2=\left(x-y\right)\left(x+y\right)$x2y2=(xy)(x+y)
$x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)$x3+y3=(x+y)(x2xy+y2)
$x^n-y^n=\left(x-y\right)\left(x^{n-1}+x^{n-2}y+\dots+xy^{n-2}+y^{n-1}\right)$xnyn=(xy)(xn1+xn2y++xyn2+yn1)
$x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\dots-xy^{n-2}+y^{n-1}\right)\quad\quad\mathrm{n\:is\:odd}$xn+yn=(x+y)(xn1xn2y+xyn2+yn1)  n is odd
$ax^{\left(2n\right)}-b=\left(\sqrt{a}x^n+\sqrt{b}\right)\left(\sqrt{a}x^n-\sqrt{b}\right)$ax(2n)b=(axn+b)(axnb)
$ax^{\left(4\right)}-b=\left(\sqrt{a}x^2+\sqrt{b}\right)\left(\sqrt{a}x^2-\sqrt{b}\right)$ax(4)b=(ax2+b)(ax2b)
$ax^{\left(2n\right)}-by^{\left(2m\right)}=\left(\sqrt{a}x^n+\sqrt{b}y^m\right)\left(\sqrt{a}x^n-\sqrt{b}y^m\right)$ax(2n)by(2m)=(axn+bym)(axnbym)
$ax^{\left(4\right)}-by^{\left(4\right)}=\left(\sqrt{a}x^2+\sqrt{b}y^2\right)\left(\sqrt{a}x^2-\sqrt{b}y^2\right)$ax(4)by(4)=(ax2+by2)(ax2by2)

 

Factorial Rules

$\frac{n!}{\left(n+m\right)!}=\frac{1}{\left(n+1\right)\cdot\left(n+2\right)\cdots\left(n+m\right)}$n!(n+m)! =1(n+1)·(n+2)(n+m)  $\frac{n!}{\left(n-m\right)!}=n\cdot\left(n-1\right)\cdots\left(n-m+1\right),n>m$n!(nm)! =n·(n1)(nm+1),n>m
$0!=1$0!=1 $n!=1\cdot2\cdots\left(n-2\right)\cdot\left(n-1\right)\cdot n$n!=1·2⋯(n2)·(n1)·n

 

Log Rules

$\log\left(0\right)=-\infty$log(0)= $\log\left(1\right)=0$log(1)=0
$\log_a\left(a\right)=1$loga(a)=1 $\log_a\left(x^b\right)=b\cdot\log_a\left(x\right)$loga(xb)=b·loga(x)
$\log_{a^b}\left(x\right)=\frac{1}{b}\log_a\left(x\right)$logab(x)=1b loga(x) $\log_a\left(\frac{1}{x}\right)=-\log_a\left(x\right)$loga(1x )=loga(x)
$\log_{\frac{1}{a}}\left(x\right)=-\log_a\left(x\right)$log1a (x)=loga(x) $\log_{x^n}\left(x\right)=\frac{1}{n}$logxn(x)=1n 
$\log_a\left(b\right)=\frac{\ln\left(b\right)}{\ln\left(a\right)}$loga(b)=ln(b)ln(a)  $\log_x\left(x^n\right)=n$logx(xn)=n
$\log_x\left(\left(\frac{1}{x}\right)^n\right)=-n$logx((1x )n)=n $a^{\log_a\left(b\right)}=b$aloga(b)=b

 

Undefined

$0^0=\mathrm{Undefined}$00=Undefined $\frac{x}{0}=\mathrm{Undefined}$x0 =Undefined
$\log_a\left(b\right)=\mathrm{Undefined}\:,\:a\le0$loga(b)=Undefined , a0 $\log_a\left(b\right)=\mathrm{Undefined}\:,\:b\le0$loga(b)=Undefined , b0
$\log_1\left(a\right)=\mathrm{Undefined}$log1(a)=Undefined

 

Complex Number Rules

$i^2=-1$i2=1 $\sqrt{-1}=i$1=i
$\sqrt{-a}=\sqrt{-1}\sqrt{a}$a=1a $$